|
Post by devster on Nov 27, 2006 18:11:55 GMT 2
I got 7.2%
|
|
|
Post by Aris on Nov 27, 2006 18:56:37 GMT 2
I got 7.2% In which subject? Based on your PM to me, you also got the "FENCE POST" question correct too! Gotta get up pretty early to put one past Devster! ;D Aris
|
|
|
Post by Aris on Dec 4, 2006 2:51:11 GMT 2
Okay, the lugnut one was easy, you just take one lugnut from each of the other tires. Here are a few more: 1. You and three friends are at an airport waiting for your plane to come in. You find an area at your departing gate where there are four empty seats. How many different possibilities are there for the four of you to arrange yourselves in these chairs? e.g. If I sit in the first chair, and Pieter sits in the second chair, and Mike sits in the third chair, and Paul sits in the fourth chair, that's one possible arrangement. 2. Jack recently purchased a farm and needs to put up 1668 feet of fence in a straight line. He has determined that he will need to put a fence post every 4 feet of fence. How many fence posts will be required? 3. You have eight coins. 7 of these coins weigh 2 ounces each, and 1 coin weighs 2.5 ounces. You are unable to determine which coin is the heavier one by looking at them or holding them. You have a scale with two pans but the scale can only be used twice. (you can perform two weighings) How can you determine which coin is the heaviest one using the scale, and using only two weighings? Good luck! Answers: 1) 4 seats, 4 friends. Let A, B, C & D represent the friends. Here are your possibilities: ABCD BACD CABD DABC ABDC BADC CADB DACB ACBD BCAD CBAD DBAC ACDB BCDA CBDA DBCA ADBC BDAC CDAB DCAB ADCB BDCA CDBA DCBA The answer is 24 2) 1668 ft of fence where a post is required every 4 ft works out to 1668/4 =417. However, whenever you build a fence, you must always start with a post, so, Jack needs 418 posts. 3) Coins in two weighings - Take two coins from the 8, and put them aside. You are left with 6 coins. Put these coins (3 on each side of the scale) and weigh them. If they're equal, then, one of the two coins you initially set aside would be the heavier one, just put one on each side of the scale to determine which one it is. If the 6 coins (3 on each side of the scale) don't balance, then, take the three from the heavier side, weigh two of them (this is your second weighing) and if they balance, then the one that you didn't weigh would be the heavier one. If they don't balance, then, of course, the one that's heavier would be evident. Hope you enjoyed these. Aris
|
|
|
Post by Aris on Dec 12, 2006 6:45:54 GMT 2
|
|
|
Post by gameboy on Dec 12, 2006 8:07:45 GMT 2
I did the one at www.iqtest.com/ and got bored half way through so guessed the remainder if the questions - i got 103
|
|
|
Post by pheldge on Dec 12, 2006 10:49:55 GMT 2
Completed at 142, but english is not my native tongue ;D
|
|
|
Post by MikeDotBe on Dec 13, 2006 18:37:24 GMT 2
made 126 may i join??? at least i could join mensa : www.mensa.org(done the test on 38/40)
|
|
|
Post by Aris on Dec 14, 2006 6:32:13 GMT 2
Yup, I think you need 124 to join, so, you just squeaked by... Aris
|
|